To complete the square you must half the co-efficient of x, square it, and add it too both sides. In this question you would halve 26, giving you 13, square it, giving you 169, the adding it to both sides. Your final equation should look like
anticipate that the cube are 6-sided. in accordance the to multiplication counting concept, the style of outcomes in a pattern area would be m*n, the place m and n are the finished style of outcomes consistent with jointed-adventure. enable m = 6, and m=n. So the finished style of outcomes is 6*6*6, that's 216.
Comments
(x^+13)^2=x^2+2x13+13^2=X^2+26X+169
so
if
X^2+26X+169-11-169=X^2+26X+169-180=X^2+26X-11=0
or X^2+26X=11
......ans -180....
to get (x + 13)(x + 13) on one side of the equation (completing the square), gives x^2 +26x + (13^2 = 169) = 11 + 169 = 180.
To complete the square you must half the co-efficient of x, square it, and add it too both sides. In this question you would halve 26, giving you 13, square it, giving you 169, the adding it to both sides. Your final equation should look like
x^2 + 26x + 169 = 180
you can then factorise this.
169 (divide the number in front of the x by 2 and square it. Add it to the other side of the equal sign to balance out the equation)
169
anticipate that the cube are 6-sided. in accordance the to multiplication counting concept, the style of outcomes in a pattern area would be m*n, the place m and n are the finished style of outcomes consistent with jointed-adventure. enable m = 6, and m=n. So the finished style of outcomes is 6*6*6, that's 216.