algebra word priblem?
avoiding a collision- a car is traveling on a road that is perpendicular to a railroad track.when the car is 30 meters from the crossing, the car's new collision detector warns the driver that there is a train 50 meters from the car and heading towards the same crossing. how far is the train from the crossing?
Comments
a^2 + b^2 =c^2
so draw your self a triangle......
car is 30 meters away from the crossing......a
the distance from the train to the car....the hypotnuse....b
c would be the distance from the train to the crossing...the unknown
a^2=900
b^2=2500
add them together
3400=c^2
square root it, and you get
58.31 meters
c² = a² + b²
50² = a² + 30²
a² = 1600
a = 40 meters
c² = a² + b²
50² = a² + 30²
a² = 1600
a = 40 meters
50 meters
the answer is 10 the sq. root of 34 0r 58.31.
follow this formula a*2 +b*2=c*2
c is missing.
ok?