This is a difference of squares and the - sign is the separator that makes it the difference of squares. Remember it's there in the middle and DON'T FORGET IT'S THERE. Then focus on the two terms on either side of the - sign: take the square root of the first term: sqrt of 4w^2 is 2w, because you take the sqrt of 4 is 2, and the sqrt of w^2 is w.
Sqrt of the second term: sqrt of 9 is 3.
Then in your final answer, write (2w-3)(2w+3) In those two parenthesis, the square root of the first term in the original equation: 4w^2-9 has to ALWAYS go first, the square root of the second term has to ALWAYS go second. And MAKE SURE that one of the parenthesis separates the two terms with a + sign, and the other one separates the two terms with a - sign.
The rule is a^2-b^2 gets factored this way: (sqrt of a-sqrt of b)(sqrt of a+sqrt of b)
Comments
How do you factor 4w^2 - 9?
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product of sum and difference of squares.
(2W -3)(2W + 3)
This is a difference of squares and the - sign is the separator that makes it the difference of squares. Remember it's there in the middle and DON'T FORGET IT'S THERE. Then focus on the two terms on either side of the - sign: take the square root of the first term: sqrt of 4w^2 is 2w, because you take the sqrt of 4 is 2, and the sqrt of w^2 is w.
Sqrt of the second term: sqrt of 9 is 3.
Then in your final answer, write (2w-3)(2w+3) In those two parenthesis, the square root of the first term in the original equation: 4w^2-9 has to ALWAYS go first, the square root of the second term has to ALWAYS go second. And MAKE SURE that one of the parenthesis separates the two terms with a + sign, and the other one separates the two terms with a - sign.
The rule is a^2-b^2 gets factored this way: (sqrt of a-sqrt of b)(sqrt of a+sqrt of b)
in the form
a^2 - b^2 = (a - b)(a + b)
difference of two squares
a² - b² = (a+b)(a-b)
(2w)² - 3²
(2w + 3)(2w - 3) -- final answer
(2w)^2-(3)^2
Use formula, a^2-b^2=(a+b)(a-b)
=(2w+3)(2w-3)