How do I solve this Algebra problem?

(m+5)^3 - (m-2)^3

**10 points right away for the right answer!**

Comments

  • = (m + 5)³ - (m - 2)²

    = m³ + 15m² + 75m + 125 - (m³ - 6m² + 12m - 8)

    = m³ + 15m² + 75m + 125 - m³ + 6m² - 12m + 8

    = 21m² + 63m + 133

    = 7(3m² + 9m + 19)

    Answer: 7(3m² + 9m + 19)

  • Solve the brackets, then complete the problem:

    (m+5)^3 - (m-2)^3

    = (m^3 + 125) - ( m^3 - 8)

    = 117 (m's cancel eachother out and 125 - -8 = 117)

    :P

    did i get it right?

  • You are not allowed to distribute the cubed you have to completely expand both sets of parentheses.

    =m^3+15m^2+75m+125-m^3+6m^2-8m+8

    =21m^2+67m+133

  • distribute so m^3+5^3 - m^3-2^3 now simplify

    m^3-125(5*5*5) -m^3- 8 (2*2*2)

    combine like terms....m^3-m^3 is zero and 125-8 is 117 and there's your answer

  • F(c)k=S(e)^X=8==D~o~o~o Problem solved

  • 21m^2+63m+133

  • (m = -125)(m + -50/21)

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