Please Explain how to do each math problem?

12(-3)+8/4y

18÷2*3+-3*4÷2

3 1/2-1 3/4

7 2/7÷2 5/6

Update:

thanks

Comments

  • Write your question clearly first before asking people. You lazy piece of sh1t

  • For the first one you have to simplify it because you cannot add a number without a variable to none with one: -36 + 2y

    For the second you use P.E.M.D.A.S

    parenthesis, exponents, multiply, add, subtract: and you get: 9

    3 1/2 - 1 3/4 you get 1 3/4

    for the fourth u convert the whole problem into a fraction, and make the 6 and the 7 common denominators, which is 42: you get 7 12/42 (divided by) 2 35/42

    Then you take the 7 and the two and add it into the equation by changing them to 42/42 and you get 306/42 (divided by) 87/42, which i have forgotten how to do, because i haven't done this since 6th grade,

  • For the 1st one you may desire to simplify it because of the fact you will now no longer upload a sort without variable to none with one: -36 + 2y For the 2d you make the main of P.E.M.D.A.S parenthesis, exponents, multiply, upload, subtract: and you get: 9 3 a million/2 - a million 3/4 you get a million 3/4 for the fourth u convert the full subject top right into a fragment, and make the 6 and the 7 consumer-friendly denominators, it particularly is 40 2: you get 7 12/40 2 (divided by utilising skill of) 2 35/40 2 then you definitely particularly take the 7 and the two and upload it into the equation by utilising skill of adjusting them to 40 2/40 2 and you get 306/40 2 (divided by utilising skill of) 87/40 2, which I particularly have forgotten the thank you to do, by way of reality i've got no longer finished this because of the fact 6th grade,

  • 1)-36 + 8/4y

    2)9

    3)7/2-7/4

    =14-7/4

    =7/4

    =1 3/4

    4)51/7 ÷ 17/6

    =18/7

    =2.57

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