ln(x^2)=16
solve
can someone explain how to do it not just give the answer
The natural log of a problem means it is a logarithm of base e, where e is some irrational number around 2.71.
basically its the following equation set of equations:
b^y = x
y = log base b of x
for the natural log, b = 2.71, and the log turns into an ln.
so in effect you will have 16 = ln(x^2)
if you undo that, you have 2.71 ^16 = x^2
solve for x.
I hope that helps, if not, go to wikipedia.org and look up natural logs, it will more clearly show the formulas there.
Comments
The natural log of a problem means it is a logarithm of base e, where e is some irrational number around 2.71.
basically its the following equation set of equations:
b^y = x
y = log base b of x
for the natural log, b = 2.71, and the log turns into an ln.
so in effect you will have 16 = ln(x^2)
if you undo that, you have 2.71 ^16 = x^2
solve for x.
I hope that helps, if not, go to wikipedia.org and look up natural logs, it will more clearly show the formulas there.