How do you factor: y^2 - 4y = 0?

Comments

  • Factor:

    y² - 4y = 0

    y(y - 4) = 0

    y = 0 OR y = 4.

  • Okay, so, what you want to do is to factor out a GCF (greatest common factor). In this case, it would be y

    y^2 - 4y = 0 <--- factor out GCF

    y (y- 4) = 0 <---- separate into two equations

    y= 0

    y= 0

    y- 4= 0 <--- add 4 to both sides to isolate y

    y= 4

    So your solutions are y= 0, 4. BUT!!!! Remember to ALWAYS, ALWAYS, ALWAYS check your solution for extraneous solutions because sometimes, the solutions will not satisfy the expression.

    If the solution results in a false statement, then the answer is not a solution to the expression. If the solution results in a true statement, then the answer IS a solution to the equation.

    Check y =0

    (0)^2 - 4(0)= 0

    0 = 0

    True.

    Check y=4

    (4)^2 - 4(4)= 0

    16 - 16 = 0

    0 = 0

    True.

    So your answers are indeed y = 0,4

  • y ( y - 4 ) = 0

    "basically since this is an equation of 1 variable, just 'factor' out a single y since there is a y in both terms, and leave the rest in parentheses."

    answers:

    y = 0

    and

    set y - 4 = 0 and solve for y

    y = 4

    so, the two solutions that satisfy this equation are: y = 0, and 4

    verification:

    (0)^2 - 4(0) = 0

    0 - 0 = 0

    (4)^2 - 4(4) = 0

    16 - 16 = 0

  • Y^2 = 4Y. Easy answer: Y = 0 or 1. Just saying.

    Of course, you could go with the hard answer, which is Y = 4. 4*4 = 4*4

    -Bitchin Tri$tann

  • it can be factored in:: y (y - 4) = 0

    so y=0 or y=4

  • y^2 -4y = 0

    y(y-4) = 0

    y=0, 4 check 0(0-4) ==> 0(4) = 0

    4(4-4) = 4(0) = 0

  • y(y-4) = 0.

    Solutions would be y = 0 and y = 4.

  • The GCF of the left side is y, so

    y(y – 4) = 0

    with solutions y = 0, 4

  • y(y - 4) = 0

    y = 0 or y = 4

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