alegbra wizards needed!!?
one canned juice drink is 25% orange juice; another is 10% orange juice. How many liters of each should be mixed together in order to get 15 L that is 18% orange juice?
How many liters of the 25% orange juice should be in the mixture?__________L
How many liters of the 10% orange juice should be in the mixture?__________L
Comments
25% juice solution = x (liters)
10% juice solution = 15 - x (liters)
Take:
(%)(Liters) + (%)(Liters) = (Total %)(Total Liters)
(0.25)(x) + (0.10)(15-x) = (0.18)(15)
0.25x + 1.5 - 0.10x = 2.7
0.15x + 1.5 = 2.7
0.15x = 1.2
x = 8
8 L of 25% juice
7 L of 10% juice
Set up a system of equations with the information that you know. Let x be the amount of "25% juice" you should add. Let y be the amount of "10% juice" you should add.
The first equation is obvious:
x + y = 15 liters
The total amount you add should be 15 liters.
Then, consider the concentration of orange juice that you need in the final mixture:
(0.25) x + (0.10) y = (0.18)(15)
The amount of actual orange juice that you have in a given container is its percentage of juice times the volume of the whole thing.
Solve those two equations simultaneously using your favorite method to reveal:
x = 8, y = 7.
In other words, you need:
8 liters of 25% juice
7 liters of 10% juice
Let x = liter of 25% OJ
let 15-x = liters of 10% OJ
solve this .25x + .10(15 -x) = 15(.18)
solving this equation will give you the amounts needs. good luck.