what is the derivative of p(x) = sqrt(f(x))?
There is a table given with the x values being 1,2,3,4 and f(x) values being 9,16,25,49
Use chain rule to get...
p'(x) = 1/(2√f(x))
I hope this helps!
p(x) = f(x) ^ (1/2 ) ==> p' = 1/2 * [f(x) ^ (-1/2)] * f ' (x)
That's pretty weird that it skipped 36
p(x) = sqrt(f(x))
p(x)= [f(x)]^(1/2)
p'(x)= (1/2) [f(x)]^(-1/2)] f'(x)
p'(x)= 1/2[f(x)]^(1/2) f'(x)
p'(x) = f'(x)/2sqrt((f(x))
Comments
Use chain rule to get...
p'(x) = 1/(2√f(x))
I hope this helps!
p(x) = f(x) ^ (1/2 ) ==> p' = 1/2 * [f(x) ^ (-1/2)] * f ' (x)
That's pretty weird that it skipped 36
p(x) = sqrt(f(x))
p(x)= [f(x)]^(1/2)
p'(x)= (1/2) [f(x)]^(-1/2)] f'(x)
p'(x)= 1/2[f(x)]^(1/2) f'(x)
p'(x) = f'(x)/2sqrt((f(x))