Question One: cos^2 theta -1 =0
Question Two: 2sin theta cos theta = cos theta
What are the two degrees that it goes by???
cos^2 theta - 1 =0
cos^2 theta = 1
cos thete = ± 1
theta = kpi , k any integer
cos^2(x) - 1 - sin^2(x)
=> sin^2(x) = 0
=> x = n(pi) for n = 1, 2, 3...
2sin(x) cos(x) = cos(x)
=> sin(x) = 1/2
Can you get the rest?
Comments
cos^2 theta - 1 =0
cos^2 theta = 1
cos thete = ± 1
theta = kpi , k any integer
cos^2(x) - 1 - sin^2(x)
=> sin^2(x) = 0
=> x = n(pi) for n = 1, 2, 3...
2sin(x) cos(x) = cos(x)
=> sin(x) = 1/2
Can you get the rest?