Algebra word problem?

A large grain silo is to be constructed in the shape of a circular cylinder with a hemisphere attached to the top. The diameter of the silo is to be 30 feet, but the height is yet to be determined. Find the height h of the silo that will result in a capacity of 11,250π ft³.

The "hemisphere attached to the top" part is giving me problems.

Comments

  • the diameter and radius for both the cylinder as well as hemisphere is the same.

    volume of hemisphere=2/3*p* r^3

    volume of cylinder=p*r^2*h(p=pie)

    total volume=11250p=2/3pr^3+p*r^2*h

    11250=(2/3r+h)r^2

    h=40m

  • The given silo structure has a cylinder on the top hemispher is placed. --- Imaging a hollow straw close at one end

    a sample picture searched from net --> http://www.easymaths.com/tank.gif

    so the diameter of the cylinder is equatl to the diameter of the hemisphere.

    so the total volume of the whole structure is

    = Volume of cylinder + volume of hemi sphere

    = pi * r * r * h + 2/3 * pi * r * r * r

    = pi * r * r (h + 2/3r) = 11,250 pi

    so r* r ( h + 2/3 r) = 11,250 ( r is 15 feet)

    so h is 40 ft

    so the height of the silo is height of the cylinder + radius of the hemisphere which is 55 feet.

  • Volume of the cylinder is V=pi*r^2*height

    Volume of the hemisphere is 4/3 * pi * r^3

    So total volume (V) is pi*r^2*height (H) + 4/3 * pi * r^3

    or

    V=pi*r^2*H+4/3*pi*r^3

    V=pi*r^2*(H+4/3*r)

    V/(pi*r^2)=H+4/3*r

    H=V/(pi*r^2) - 4/3*r

    Substituting 15 for r and 11250 pi for V,

    H=((11250*pi)/(225*pi)) - 20

    H=50-20

    H=30

    The cylinder is 30 feet high. Because it is also 30 feet wide, a hemisphere on top will add an additional 15 feet, and the topmost point of the silo is 45 feet above the base.

    Edit: I used the formula for the volume of a sphere, not of a hemisphere. So my answer will be wrong. Ignore it.

  • Vol. of hemisphere = 2/3 pi r^3

    = 2/3 pi * 3375 cu ft = 2250 pi ft^3

    Therefore vol of cylindrical part = (11250 - 2250) pi ft^3

    = 9000 pi ft^3

    Vol of cylinder = pi r^2 *h

    = 225 pi * h

    Therefore 225 pi * h = 9000 pi

    therefore 225 h = 9000 (Dividing both sides by pi)

    therefore h = 40 (This is height of cylinder)

    Therefore total height = 55 ft (height of cylinder + hemisphere)

  • Okay, volume for half a sphere is (.5)(4/3)pi*r^3. SO, the hemisphere is

    .5(4/3)pi*(30/2)^3=2250pi.

    SO, the height is (11,250pi-2250)/(pi*(30/2)^2) = 40.

    SO, it should be 40 feet.

  • If the scholars cutting-edge grade is a ninety% then we’re of path assuming it’s out of a hundred% ninety/a hundred Now as a results of fact the scholars grade superior 20% from the final grading era then you definately upload that to the previous a hundred% supplying you with ninety/ a hundred and twenty = .75 and because grades are in opportunities you multiply .75 by making use of a hundred supplying you with 75% as a results of fact the scholars previous grade

Sign In or Register to comment.