Algebra problem help?

Comments

• rebecca-phillips_6096582ac753e

  May 2021

  (2-x)/4 + 3 = 1

  Subtract 2 from both sides:

  (2-x)/4 = -2

  Multiply both sides by 4 to cancel off the denominator:

  2 - x = -8

  Subtract 2 from both sides:

  -x = -10

  Divide both sides by -1:

  x = 10

  ----------------------

  3 + z/4 + 5 = 19

  Add the like terms together:

  z/4 + 8 = 19

  Subtract 8 from both sides:

  z/4 = 11

  Multiply both sides by 4 to cancel off the denominator:

  z = 44
• pranil

  May 2021

  (2 – x)/4 + 3 = 1

  (2 – x)/4 = 1 – 3

  (2 – x)/4 = – 2

  (2 – x) = – 8

  – x = – 8 – 2

  – x = – 10

  x = 10

  3 + z/4 + 5 = 19

  z/4 + 8 = 19

  z/4 = 19 + 8

  z/4 = 27

  z = 27 × 4 = 108

  or is it

  (3 + z)/4 + 5 = 19

  (3 + z)/4 = 19 – 5

  (3 + z)/4 = 14

  (3 + z = 56

  z = 56 – 3 = 53

  ----
• nathan-turner_6096582c38bd3

  May 2021

  ((2 - x) / 4) + 3 = 1

  (2 - x) / 4 = -2

  2 - x = -8

  2 + 8 = x

  x = 10
• michael

  May 2021

  better write (2 - x) / 4 + 3 = 1

  so:

  (2-x)/4 = 1 - 3 = -2

  2 - x = -8

  -x = -8 - 2 = -10

  x = 10

  hope it'll help !
• thomas-english

  May 2021

  First subtract 3 from both sides and you now have (2-x)/4 = 4

  Then to get rid of the fraction you multiply both sides by 4 and get 2 - x = 16

  Get x by itself by subtracting 2 from both sides and get -x = 14.

  Now divide (or multiply) both sides by -1 to get a positive x and your answer becomes x = -14.