Easy math problem (algebra 2)?

Comments

• anonymous

  May 2021

  x^2 - 19 = 6

  Begin by subtracting 6 both sides to get it over to the other..

  x^2 - 19 - 6 = 6 - 6

  x^2 - 25 = 0

  This is a difference of squares, difference of squares are a special product in the form (a^2 - b^2).

  They are factored in the form (a - b)(a + b)..thus...

  x^2 - 25 = 0

  (x)^2 - (5)^2 = 0

  (x - 5)(x + 5) = 0

  Now according to the zero product property (ab = 0, where a = 0 or b = 0), we will set each factor equal to 0 and solve for x.

  x - 5 = 0

  x - 5 + 5 = 0 + 5

  x = 5

  x + 5 = 0

  x + 5 -5 = 0 - 5

  x = -5

  x = 5 or x = -5

  Thus the solutions are 5 or -5.
• andy-johnson_60a356ed93d11

  May 2021

  Are you sure that's Algebra 2? Looks like pre-algebra to me

  x² - 19 = 6

  Add 19 to both sides

  x² = 25

  Take the square root of both sides

  x = 5, x = -5
• ranjankar

  May 2021

  x^2 -19 = 6

  ADD 19

  x^2 = 25

  X = +5 OR -5 ANSWER
• ray-s

  May 2021

  x² - 19 = 6                 ← Add 19 to both sides

         x² = 25               ← Now, take the square root of both sides

          x = ±√25            ← by the square root property

          x = ±5

          x = 5 , -5            ← ANSWER

  Have a good one!

  .
• pascal

  May 2021

  x = 5 or -5
• engineer

  May 2021

  Write as x^2 = 25 and take the square root of 25.
• tracy-walker_60a356efdad57

  May 2021

  x^2-19=6

  x^2 - 19 - 6 = 6 - 6

  x^2 - 25 = 0

  (x+5)(x-5) = 0

  x = -5, 5...............ANS
• the-me

  May 2021

  x^2-25=0

  (x+5)(x-5)=0

  x = 5 or x = -5