MATH WORD PROBLEM / MATH WORD PROBLEM?
The time a person takes to paddle a keyak 2miles downstream is the same as the time to paddle half a mile upstream. If the rate of the current is 3mph, what is the persons paddling rate in still water?
any info would be great, thanks
Comments
Paddling rate—r:
2/(r + 3) = (1/2)/(r - 3)
2r - 6 = 1/2r + 3/2
4r - 12 = r + 3
3r = 15
r = 5
Answer: 5 mph is the paddling rate of a person.
Proof:
2mi/(5 + 3 mph) = (1/2mi)/(5 - 3 mph)
2mi/8mph = (1/2mi)/2mph
1/4 hr = 1/4 hr
(Vsw+3)t=2 ,
(Vsw-3)t=0.5 ,Divide both sides together,
Vsw+3/Vsw-3=4
Vsw+3=4Vsw-12,15=3Vsw,=====> Vsw=paddling rate in still water=
=15/3=5mph
God bless you.