Num triângulo retângulo,um cateto mede 10cm e o cosseno do ângulo agudo adjacente a ele vale 0,6?

Comments

• isa-a

  May 2021

  | \

  |a \h

  10 | \

  |_ _\

  c1

  o cosseno do ângulo agudo adjacente (a) = 0,6 = 10/h

  ==> h = 10/0,6 = 50/3 cm

  usando pitágoras

  c1 = [ (50/3)^2 - 10^2]^1/2

  = [ 2500/9 - 100]^1/2

  = [1600/9]^1/2

  ========================c1 = 40/3

  = [100 x 35]^1/2 = [ 10^2 x 35 ] ^1/2

  = 10V35

  c1 = 10V35

  V indica raiz quadrada
• connor-morgan_60a0c1a41f82d

  May 2021

  cateto/hipotenusa=0,6

  10cm/hipotenusa=0,6

  hipotenusa=10/0,6

  hipotenusa=100/6

  (100/6)²=10²+c²

  c²=(100/6)²-10²

  c²=(10.000/36)-100

  c²=(10.000-3.600)/36

  c²=6.400/36

  c=²V(6.400/36)

  c=80/6

  c=40/3

  h=100/6

  h=50/3