Potassium nitrate decomposes to potassium nitrite and oxygen: 2KNO3(s)→Δ2KNO2(s)+O2(g)?
Using the ideal gas law equation, calculate the volume, in liters, of the O2 produced if the decomposition of 56.0g of KNO3 takes place at 25∘C and 1.19atm
Using the ideal gas law equation, calculate the volume, in liters, of the O2 produced if the decomposition of 56.0g of KNO3 takes place at 25∘C and 1.19atm
Comments
2 KNO3 → 2 KNO2 + O2
(56.0 g KNO3) / (101.1032 g KNO3/mol) x (1 mol O2 / 2 mol KNO3) = 0.27694 mol O2
V = nRT / P = (0.27694 mol) x (0.08205746 L atm/K mol) x (25 + 273) K / (1.19 atm) = 5.69 L O2