Did I do this correctly
Find the oblique asymptote of
y = (3x - 1)/(2x^2 + x - 6)
I said
y = 3/(2x)
If not can you please show me how thanks
SORRY...the graph has no oblique asymptote...
degree of the top = 1 more than that of the bottom for oblique
HA is y = 0 , VAs are x = -2 & 3/2
yes actually.
Comments
SORRY...the graph has no oblique asymptote...
degree of the top = 1 more than that of the bottom for oblique
HA is y = 0 , VAs are x = -2 & 3/2
yes actually.