C3H8 (g) + 5 O2 (g) ---> 3 CO2 (g) + 4 H2O (l)?
1) Identify which reactant is totally consumed and which is in excess.
2) Determine the mass of each product formed when the reaction is complete.
Im having a hard time grasping this concept. I understand parts, but i get stuck along the way. I need a nice clear laid out explanation of how to do it? 
Comments
1) Well since the mass of each reactant is not specified then the only thing you have to do is look at the equation, you have 1mol of C3H8 and 5mol of O2, thus C3H8 is the limited reagant and O2 is in excess.
2) I am not sure about this one but if the mass needs to be in grams it would be 132g of CO2 and 72g of water
http://g.web.umkc.edu/gounevt/Weblec211/PDF/lec23%...